The math test in middle school was like this.

The approach to tackling the task is commendable.

Aren’t you going to calculate the expected value of the total of the two dice rolled?

It’s a 1/2 chance of coming out or not.

Rather, I don’t understand how to use the formula.
The probability that the second die shows the same number as the first die, regardless of what the first number is, is 1/6, and I can understand that intuitively.

The probability of getting face Z on the first die A is 1/6.
The probability of rolling that number on the second die B is 1/6.
There are six patterns for a certain eye Z.
1/6 × 1/6 × 6 = 1/6

It seems like there are quite a few people here who might not understand.

dice2d6=1 1 (2)

I can’t remember any of the math I learned in junior high or high school at all.
I understand this, but things like sets and matrices are absolutely impossible for me.

How many times do I have to do it to get the correct value?

I remembered the strategy of actually drawing and measuring in problems that ask to find the length of a line from part of the dimensions of a shape.

What is the probability of rolling two of the same number in Chin-Chiro along with other numbers?

I am smart, so I will write out all the patterns.

It’s because of 6/6^6…The probability is too low!

1/6!

The technique of writing a tree diagram as small as possible to fit on the edge of the exam paper is honed.

You can understand this in your head without even doing the calculations, right?

Don’t compete with the silly heroine from the manga!

How many times should I swing to make it reasonable? If asked that, I’ll just give up thinking!

Aren’t we going to list all the combinations?

The probability of rolling a 1 on a die numbered 1 to 6 is 1/6, so it’s something you can understand by intuition rather than calculation.

Since the probabilities of the dice rolls are already engraved in my mind, I get a bit confused when told to recalculate.

Becoming or not becoming a double number.
In other words, it means a 50% chance…

Let’s go, let’s go!

The probability that the result of die B is x, given that the result of die A is x, is 1/6.

For a math class assignment, we were told to roll a die 10,000 times and record the results.

The result of the calculation turns out to be like that!
Alright!
Roll the dice!

I will write everything like 1-1 1-2.

Is it 1/2 whether we get a double number or not?
dice2d6=1 4 (5)

I think most anonymous users are aware that what they’re saying is a joke.
There are likely some people who think that there’s about a 1 in 2 chance of it being serious, at a ratio of about 1 in 6.

Instead of writing out and counting the patterns, you’re figuring them out in practice…
How many trials are you going to take…?

It seems there are quite a few people who write everything.
I don’t think there are many people who throw dice themselves.

A story about getting scolded by Chiko-chan, calling a probability theory teacher late at night, being answered in a rude manner, and having the phone hung up on me.

Writing everything down is quite effective, you know.
You’ll start to notice it after writing to a certain extent.

The secret of the triangle is, you know.

It’s called a dice.

Kaiji! I want to hear your opinion!

I thought it was unreasonable to assume that a die in such a problem is a standard six-sided die.

It’s like just writing down the answers that can be solved with brute force on a test I completely don’t understand, and getting a few points…